c++ - What value does a Pointer to a Pointer print if not a single dereference operator is used at all? -

i have tried output of following code. but, don't yet understand might value of q represent.

i understand *q points p implying that, printing *q print address of p, **q print value @ address p points to, i.e., x(=5).

#include <iostream> using namespace std; int main() {     int x=5;     int *p,**q;     p=&x;     q=&p;     cout<<q;     return 0; } 

so q alone represent? value printed when q printed?

p.s: i'm c++ noob , have searched answer question elsewhere , seem not find it. if find answer somewhere else, please forgive me , notify me , i'll remove question.

you say:

printing *q print address of p

however not true. printing q print address of p. after all, assigned in doing q = &p;.

printing *q print value of p , address of x.