python 2.7 - What is the difference between these two examples? -

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i going through python tutorial -

static method, class method

class pizza(object):     @staticmethod     def mix_ingredients(x, y):         return x + y      def cook(self):         return self.mix_ingredients(self.cheese, self.vegetables)  >>> pizza().cook pizza().cook false >>> pizza().mix_ingredients pizza.mix_ingredients true >>> pizza().mix_ingredients pizza().mix_ingredients true

i don't quite understand result of ---> pizza().cook pizza().cook - > why different?

and pizza().mix_ingredients pizza.mix_ingredients -> difference between having bracket , no bracket?

finally, static method, why final result true?

many thanks!

a way think see cook method being 1 per pizza, whereas pizzas share same @staticmethod mix_ingrecdients.

so pizza() gives new pizza, pizza().cook cook method of specific pizza (indicated self) so,

pizza().cook pizza().cook

will therefore false.

this partially answers next part of question. pizza type , pizza() instance of type. when refer tho static method gives same function:

>>> pizza().mix_ingredients <function mix_ingredients @ 0x7f62a5eae668> >>> pizza.mix_ingredients <function mix_ingredients @ 0x7f62a5eae668>

if try instance method, "bound" , "unbound" functions.


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