c++ - How to extend a line segment in open cv using python -

i having 2 end points of line segment , want extend line. found following algorithm through website

          lengthab = sqrt((a.x - b.x)^2 + (a.y - b.y)^2)            c.x = b.x + (b.x - a.x) / lengthab * length;           c.y = b.y + (b.y - a.y) / lengthab * length; 

but can't output while implement on program. need int value cx , cy in float.

![ a(x,y)=(200,140) , b(x,y)=(232,146) ][1]

  import numpy np   import cv2   import math   img = np.zeros((500,500,3), np.uint8)   lenab = math.sqrt((200-232)**2+(158-146)**2)   length = 100   cx = 232 + (232-200) / lenab*length   cy = 146 + (146-158) / lenab*length   cv2.line(img,(200,158),(cx,cy),(33,322,122),3)   cv2.imshow('tha',img)   cv2.waitkey(0)   cv2.destroyallwindows() 

my o/p screen :

      traceback (most recent call last): file "e:/nan/inclined_line.py", line 9, in <module> cv2.line(img,(200,158),(cx,cy),(33,322,122),3) typeerror: integer argument expected, got float 

from error passing floating point value cv2.line. convert float integer so:

 cv2.line(img,(200,158),(int(math.floor(cx)),int(math.floor(cy))),(33,322,122),3)