How to get elements of first array of hashes that not present in second array of hashes in Perl -

how elements of first array of hashes not present in second array of hashes. example, have 2 arrays of hashes:

my $arr1 = [     { id => 1, name => 'element 1'},     { id => 2, name => 'element 2'},     { id => 3, name => 'element 3'},     { id => 4, name => 'element 4'},     { id => 5, name => 'element 5'}, ];  $arr2 = [     { id => 1, name => 'element 1'},     { id => 3, name => 'element 3'},     { id => 5, name => 'element 5'}, ]; 

result should be:

my $arr3 = [     { id => 2, name => 'element 2'},     { id => 4, name => 'element 4'}, ]; 

you can build hash look-up , filter @$arr1 elements,

my %seen; @seen{ map $_->{id}, @$arr2 } = (); # $seen{$_->{id}} = undef @$arr2; # or foreach instead of hash slice  $arr3 = [ grep{ !exists $seen{$_->{id}} } @$arr1 ];